www.ypnh.net > 设x,y满足约束条件x≥0y≥0x3A+y4A≤1,若z=x+2y+3x+1的最小值为32,则A的值...

设x,y满足约束条件x≥0y≥0x3A+y4A≤1,若z=x+2y+3x+1的最小值为32,则A的值...

解答:解:∵x+2y+3x+1=1+2×y+1x+1,而y+1x+1表示过点(x,y)与(-1.-1

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